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.
.
. Calculate the pressure exerted by each leg.
.
and a weight of 10 kg is hung on it. The wire on the right is made of aluminium, its length is 3 m, and its cross-sectional area is 
. What is the mass of the weight that we have to hang on the second wire so that its extension is the same as the first wire? The Young modulus of copper is 
and that of aluminium is 
.
. By how much can a 2 m long brass wire be stretched so that it does not deform plastically?
, as shown.
?
and a cross-section of 
. It is designed to compress 
when under maximum, evenly distributed, load. The Young modulus of steel is 
. What is the maximum load it can support?
and cross-sectional area 
, equally support an object weighing 
. The weight of the object causes the rods to contract by 
. The rods obey Hooke’s law. What is the Young modulus of steel?
the diameter is 
. At end 
the diameter is 
.
?
is stretched within its limit of proportionality by a tensile force of 
. The Young modulus of copper is 
. What is the strain in the wire?
length of steel wire and a 
length of brass wire are joined together. The combined wires are suspended from a fixed support and a force of 
is applied, as shown.
. The Young modulus of brass is 
. Each wire has a cross-sectional area of 
. The wires obey Hooke’s law. What is the total extension? Ignore the weights of the wires.
in length. The Young modulus 
of the plastic is 
and the Young modulus 
of the nylon is 
. The composite rod will break when its total extension reaches 
. What is the greatest tensile stress that can be applied to the composite rod before it breaks?
of the material of the wire and of the force per unit extension 
of the wire. For a wire of length 
and cross-sectional area 
, what is the relation between 
and cross-sectional area 
. The wire extends a distance 
when mass 
is hung from the other end of the wire. What is an expression for the Young Modulus 
of the metal?
in a material is given by the equation shown.
in the same material is given by the equation shown.
has a uniform cross-sectional area of 
. A tensile force of 
is applied to the wire. This causes the wire to extend by 
up to its limit of proportionality. Calculate the Young modulus of the wire.
. Another experiment is carried out using a wire of the same steel, but of twice the length and half the diameter. What value is obtained for the Young modulus in the second experiment?
can be determined from measurements made when a wire is stretched. Which quantities would be measured in order to determine 
and diameter 
. The lift drops 
when a man of mass 
steps into the lift. What is the best estimate of the value of the Young modulus of the steel?
and for brass is 
. What is the ratio of the extension of the steel to the extension of the brass?
